Geometry in Chemistry: Why Molecules Have the Shapes They Do
Quick Answer
Geometry in chemistry is how electron groups arrange themselves around a central atom to stay as far apart as possible. Count the groups (bonds plus lone pairs) to get the electron geometry, then ignore the lone pairs to name the molecular shape. That one step also gives you the bond angle, the hybridization, and whether the molecule is polar.
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Table of Contents
- Why Geometry Matters in Chemistry
- Bond Angles and Shapes (VSEPR)
- Hybridization and Orbital Geometry
- Molecular Polarity: Geometry Plus Vectors
- Crystal Structures and Unit Cells
- Common Geometry Mistakes in Chemistry
- Practice Problems With Answers
- Tips for ALEKS, WebAssign, and Mastering Chemistry
- Getting Help With Chemistry
- FAQ
Why Geometry Matters in Chemistry
Shape decides how a molecule behaves. It controls whether the molecule is polar, how it packs with its neighbors, and so its boiling point and solubility. In organic chemistry it also decides which atoms a reaction can reach. Water is bent and polar, which is why it is a liquid at room temperature. Carbon dioxide has polar bonds but a linear shape, so it is nonpolar and a gas.
The math is mostly geometry you already know: angles, symmetry, vectors, and volumes. If the algebra side is what trips you up, see our guide to algebra in chemistry.
Bond Angles and Shapes (VSEPR)
VSEPR (valence shell electron pair repulsion) says electron groups around a central atom repel each other and settle as far apart as possible. A group is a single, double, or triple bond, or a lone pair. Use this routine:
- Draw the Lewis structure.
- Count electron groups on the central atom. This gives the electron geometry.
- Count how many of those groups are lone pairs.
- Name the molecular shape from the bonded atoms only.
| Groups | Lone pairs | Molecular shape | Example | Approx. angle | Hybridization |
|---|---|---|---|---|---|
| 2 | 0 | Linear | CO2 | 180° | sp |
| 3 | 0 | Trigonal planar | BF3 | 120° | sp2 |
| 3 | 1 | Bent | SO2 | slightly under 120° | sp2 |
| 4 | 0 | Tetrahedral | CH4 | 109.5° | sp3 |
| 4 | 1 | Trigonal pyramidal | NH3 | about 107° | sp3 |
| 4 | 2 | Bent | H2O | about 104.5° | sp3 |
| 5 | 0 | Trigonal bipyramidal | PCl5 | 90° and 120° | sp3d |
| 5 | 1 | Seesaw | SF4 | less than 90° and 120° | sp3d |
| 5 | 2 | T-shaped | ClF3 | slightly under 90° | sp3d |
| 5 | 3 | Linear | XeF2 | 180° | sp3d |
| 6 | 0 | Octahedral | SF6 | 90° | sp3d2 |
| 6 | 1 | Square pyramidal | BrF5 | slightly under 90° | sp3d2 |
| 6 | 2 | Square planar | XeF4 | 90° | sp3d2 |
Lone pairs take up more room than bonding pairs, so they squeeze the bonded atoms closer together. Four electron groups give three different angles for that reason:
Worked example: ClF3 from Lewis structure to shape
Most wrong answers start with a wrong Lewis structure, so here is the full routine on chlorine trifluoride.
- Count valence electrons. Chlorine has 7 and each of three fluorines has 7, so 7 + 3(7) = 28.
- Place the bonds. Put chlorine in the center with three single bonds to fluorine. That uses 6 electrons.
- Finish the outer atoms. Give each fluorine three lone pairs, which is 18 electrons. Running total: 24.
- Put the rest on the central atom. 28 − 24 = 4 electrons, which is two lone pairs on chlorine. Chlorine now has 10 electrons around it, which is allowed for a period 3 element.
- Count electron groups. Three bonds plus two lone pairs is 5 groups, so the electron geometry is trigonal bipyramidal.
- Place the lone pairs. Lone pairs go in the equatorial positions first, because that keeps them farther from the other groups (fewer 90° repulsions). The three fluorines are left in a T shape.
- Name the shape and check polarity. The molecular shape is T-shaped, with F–Cl–F angles slightly under 90° because the lone pairs push the fluorines together. The bond dipoles do not cancel, so ClF3 is polar, and the hybridization is sp3d.
The same steps work for every row in the table. The only things that change are the electron count and how many lone pairs are left over. Here is how lone pairs reshape both the five-group and six-group families:
Where 109.5 degrees comes from
The tetrahedral angle is geometry, not a memorized number. Put the central atom at the center of a cube and run bonds to two corners that do not share an edge, such as (1, 1, 1) and (1, −1, −1). The dot product is 1 − 1 − 1 = −1, and each vector has length √3, so cos θ = −1/3 and θ = 109.47°.
Hybridization and Orbital Geometry
Hybridization matches the number of electron groups. Two groups mean sp, three mean sp2, four mean sp3. Five and six groups are labeled sp3d and sp3d2 in most general chemistry courses, although some modern treatments explain those molecules without d orbitals. Use whichever convention your textbook uses.
Hybridization also tells you the bonding pattern. In ethene (C2H4), each carbon has three groups, so it is sp2 and planar at about 120°. The C=C double bond is one sigma bond plus one pi bond, and the pi bond is what locks the molecule flat. In organic chemistry this planar versus tetrahedral difference decides which side of an atom a reagent can attack. See our organic chemistry help page for more on that.
Molecular Polarity: Geometry Plus Vectors
A bond dipole is a vector that points toward the more electronegative atom. A molecule is polar only if those vectors do not cancel. That makes polarity a geometry question:
- Symmetric shapes with identical outer atoms cancel. CO2 (linear) and BF3 (trigonal planar) have polar bonds but are nonpolar overall.
- Lone pairs and bent or pyramidal shapes usually do not cancel. H2O and NH3 are polar.
- Square planar XeF4 cancels even though it has lone pairs, because the two lone pairs sit opposite each other.
You can add the vectors with trigonometry. For a bent molecule with bond angle θ and two equal bond dipoles of size μ, the net dipole is 2μ cos(θ/2). For water, θ = 104.5°, so the net is 2μ cos(52.25°) = about 1.22μ. For a linear molecule, θ = 180° and cos 90° = 0, so the net is zero.
Crystal Structures and Unit Cells
Crystals repeat a small box called a unit cell. There are seven crystal systems (cubic, tetragonal, orthorhombic, hexagonal, trigonal, monoclinic, and triclinic). General chemistry usually focuses on the three cubic arrangements:
| Cubic unit cell | Atoms per cell | Coordination number | Fraction of space filled |
|---|---|---|---|
| Simple cubic | 1 | 6 | 52% |
| Body-centered cubic | 2 | 8 | 68% |
| Face-centered cubic | 4 | 12 | 74% |
Worked example: Copper is face-centered cubic with an edge length of 361 pm and a molar mass of 63.55 g/mol. What is its density?
- Convert the edge to centimeters. 361 pm = 3.61 × 10−8 cm.
- Find the cell volume. V = a3 = (3.61 × 10−8 cm)3 = 4.70 × 10−23 cm3.
- Find the mass in one cell. Four atoms per cell, so 4 × 63.55 g/mol ÷ 6.022 × 1023 atoms/mol = 4.22 × 10−22 g.
- Divide. Density = 4.22 × 10−22 g ÷ 4.70 × 10−23 cm3 = 8.97 g/cm3.
That is close to copper’s accepted density of about 8.96 g/cm3, which is a good sign the setup is right. The most common error is forgetting to convert picometers to centimeters before cubing.
Common Geometry Mistakes in Chemistry
| Mistake | Quick fix |
|---|---|
| Mixing up electron geometry and molecular geometry | Electron geometry counts lone pairs. Molecular shape names only the atoms. Read what the question asks for. |
| Using ideal angles for molecules with lone pairs | Lower the angle. Water is about 104.5°, not 109.5°. |
| Calling a molecule polar because it has polar bonds | Check whether the bond dipoles cancel by symmetry. CO2 and BF3 do. |
| Skipping the Lewis structure | You cannot count electron groups without it. Draw it first, every time. |
| Forgetting a double bond counts as one group | Count regions of electrons, not number of bonds. CO2 has two groups. |
| Not converting units in unit-cell problems | Convert pm to cm before you cube the edge length. |
Practice Problems With Answers
Try each problem first, then check the worked answers below. Problem 7 uses the Lewis-structure routine from the ClF3 example.
- BF3. Give the molecular shape, bond angle, and polarity.
- NH3. Give the molecular shape, approximate bond angle, and polarity.
- Ethene. What is the hybridization of each carbon, and what bonds make up the C=C?
- XeF4. Give the electron geometry, molecular shape, and polarity.
- Dipole vectors. A bent molecule has a 120° bond angle and two bond dipoles of 1.0 D each. What is the net dipole?
- Unit cell. Silver is face-centered cubic with an edge length of 409 pm and a molar mass of 107.87 g/mol. Find its density.
- Lewis structure to shape. Draw the Lewis structure for SF4, then give its electron geometry, molecular shape, and polarity.
Answers and Worked Solutions
- Trigonal planar, 120°, nonpolar. Boron has three bonding groups and no lone pairs. The three B–F dipoles are equal and 120° apart, so they cancel.
- Trigonal pyramidal, about 107°, polar. Nitrogen has four groups: three bonds and one lone pair. The bond dipoles do not cancel, so the molecule is polar.
- Each carbon is sp2. Each has three groups (two C–H bonds and the C=C), so the geometry is trigonal planar at about 120°. The C=C is one sigma bond plus one pi bond.
- Octahedral electron geometry, square planar shape, nonpolar. Xenon has 8 valence electrons. Four go to bonds and four remain as two lone pairs, so there are six groups. The lone pairs sit opposite each other, leaving four fluorines in a plane, and the bond dipoles cancel.
- 1.0 D. Net = 2μ cos(θ/2) = 2(1.0) cos(60°) = 2(1.0)(0.5) = 1.0 D.
- 10.5 g/cm3. Edge = 4.09 × 10−8 cm, so V = 6.84 × 10−23 cm3. Mass of four atoms = 4 × 107.87 ÷ 6.022 × 1023 = 7.17 × 10−22 g. Density = 7.17 × 10−22 ÷ 6.84 × 10−23 = 10.5 g/cm3.
- Trigonal bipyramidal electron geometry, seesaw shape, polar. Valence electrons: 6 + 4(7) = 34. Four S–F bonds use 8, the fluorines take 24 more, and the remaining 2 electrons form one lone pair on sulfur. That is 5 groups. The lone pair sits in an equatorial position, leaving a seesaw. The bond dipoles do not cancel, so SF4 is polar (sp3d).
Reference values: angles and unit-cell figures are standard general chemistry textbook values. Your course may round differently, so match your instructor’s conventions.
Tips for ALEKS, WebAssign, and Mastering Chemistry
Geometry questions show up on every major chemistry platform, and the answer formats vary by course and problem. A few habits help everywhere:
- Read what is being asked. Electron geometry and molecular shape are different answers.
- Draw the Lewis structure before you pick a shape. Most wrong answers start with a wrong structure.
- Check the entry instructions for angles. Some problems ask for a rounded number, others for a range. Follow the format shown.
- Look at how the platform names shapes. Use its exact wording, such as “trigonal pyramidal” and not “pyramid”.
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Getting Help With Chemistry
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More in this series:
- Algebra in Chemistry
- Logarithms in Chemistry: pH, pOH, and Buffers
- Dimensional Analysis in Chemistry
- Molecular Geometry of SO32−
FAQ: Geometry in Chemistry
What is the difference between electron geometry and molecular geometry?
Electron geometry counts every electron group around the central atom, including lone pairs. Molecular geometry names the shape made by the bonded atoms only. Water has tetrahedral electron geometry and a bent molecular shape.
Why do lone pairs make bond angles smaller?
A lone pair is held by one nucleus and spreads out more than a bonding pair, so it repels neighboring groups more strongly. That pushes the bonds closer together. The angle drops from 109.5 degrees in methane to about 107 in ammonia and about 104.5 in water.
Why is water bent instead of linear?
Oxygen in water has four electron groups: two bonds and two lone pairs. Those four groups point toward the corners of a tetrahedron, so the two hydrogens sit about 104.5 degrees apart, not 180.
How do I find hybridization from geometry?
Count electron groups on the central atom. Two groups give sp, three give sp2, four give sp3, five give sp3d, and six give sp3d2. A lone pair counts as a group.
How do I tell if a molecule is polar?
Find the molecular shape, draw the bond dipoles toward the more electronegative atoms, and check whether they cancel. Symmetric shapes with identical outer atoms, such as CO2 and BF3, are nonpolar. Bent and pyramidal shapes are usually polar.
Can I predict a shape without a Lewis structure?
Not reliably. You need the Lewis structure to count lone pairs and electron groups, and the shape depends on both. For ions like sulfite, getting the structure right is most of the work.
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